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Home/ Questions/Q 7677913
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T17:31:43+00:00 2026-05-31T17:31:43+00:00

I am creating a calculator application for all types of mathematical algorithms. However, I

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I am creating a calculator application for all types of mathematical algorithms. However, I want to identify if a root is complex and then have an exception for it.
I came up with this:

if x == complex():
    print("Error 05: Complex Root")

However, nothing is identified or printed when I run the app, knowing that x is a complex root.

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  1. Editorial Team
    Editorial Team
    2026-05-31T17:31:44+00:00Added an answer on May 31, 2026 at 5:31 pm

    I’m not 100% sure what you’re asking, but if you want to check if a variable is of complex type you can use isinstance. For example,

    x = 5j
    if isinstance(x, complex):
        print 'X is complex'
    

    prints

    X is complex
    
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