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Home/ Questions/Q 8051635
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T07:20:41+00:00 2026-06-05T07:20:41+00:00

I am creating a client to my RESTful Web Service. In this case, my

  • 0

I am creating a client to my RESTful Web Service.
In this case, my Server will not always return the expected object (e.g. nothing found on a given parameter, so return is NULL).

@GET
@Path("/person/{name}")
@Produces("application/xml")
public Person getPerson(@PathParam("name") String name) {
    return people.byName(name);
}

The byName() method will return NULL if the given name is not found. Upon unmarshalling the given object, this will raise an exception. What is the most common and clean way to just result in an if/else statement or something to handle the returns in different ways?

JAXBContext jcUnmarshaller = JAXBContext.newInstance(Person.class);
Unmarshaller unmarshaller = jcUnmarshaller.createUnmarshaller();
return (Person) unmarshaller.unmarshal(connection.getInputStream());

SOLUTION

getPerson( ) throws WebApplicationException { 
    throw new WebApplicationException(404);
}
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  1. Editorial Team
    Editorial Team
    2026-06-05T07:20:42+00:00Added an answer on June 5, 2026 at 7:20 am

    The idiomatic way to handle such situations is to return 404 Not Found response code. With jax-rs you can throw WebApplicationException:

    @GET
    @Path("/person/{name}")
    @Produces("application/xml")
    public Person getPerson(@PathParam("name") String name) {
        Person personOrNull = people.byName(name);
        if(personOrNull == null) {
          throw new WebApplicationException(404);
        }   
        return personOrNull;
    } 
    
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