Home/ Questions/Q 5992925
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-22T23:36:08+00:00

I am creating a countdown to count the time between a match of the

  • 0

I am creating a countdown to count the time between a match of the euro2012 that I intend to watch.
I’ve come with a working version of it but I don’t understand why it gives me sometimes negative values.
I think it has to do with the way I wrote it, using the getTime() method.
Here is my code, could you guys help me find out to solve those negative values?
Thank you very much in advance.

<body onload="timeto2012()">
<script type="text/javascript">
 function timeto2012() {
 var euro2012 = new Date(2012, 5, 10, 20, 45);
 var euro2012ms = euro2012.getTime();
var now = new Date();
var nowms = now.getTime();

var diff = euro2012ms - nowms;

var seconds = 1000;
var minutes = seconds*60;
var hours = minutes*60;
var days = hours*24;
var years = days*365;

var ddays = diff/days;
var dhours = (ddays - Math.round(ddays,1))*24;
var dminutes = (dhours - Math.round(dhours))*60;
var dseconds = (dminutes - Math.round(dminutes))*60;

document.getElementById("time").innerHTML='' + Math.round(ddays,1) +' days '+ Math.round(dhours,1) +' hours '+ Math.round(dminutes,1) +' minutes '+ Math.round(dseconds,1) + ' seconds remaining';

}

t=setInterval(timeto2012,500);

</script>   
<div id="time"></div>
</body>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    KOGI has the answer to your problem: You should use Math.floor instead of Math.round:

    When there’s x minutes and 30 – 59 seconds left, the (x - Math.round(x)) would be equivalent to (x - (x + 1)) after the rounding was done. 

    var ddays = diff/days;
var dhours = (ddays - Math.floor(ddays))*24;
var dminutes = (dhours - Math.floor(dhours))*60;
var dseconds = (dminutes - Math.floor(dminutes))*60;

    Fiddle: http://jsfiddle.net/YHktx/3/

    • 0