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Home/ Questions/Q 6068461
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:43:02+00:00 2026-05-23T09:43:02+00:00

I am creating a dynamic form to submit with few input elements, but it

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I am creating a dynamic form to submit with few input elements, but it does not send a request. I use fiddler to check

Here is my code

var form_ref = document.createElement("form");
form_ref.id = "viewform";
form_ref.name = "viewform";
form_ref.action = "/csm/showResult.action";
form_ref.method = "post";
form_ref.target = "_self";

var cfgidField = document.createElement("input");
cfgidField.name = "cfgid";
cfgidField.type = "text";
cfgidField.value = configid;
form_ref.appendChild(cfgidField);

var cfgnameField = document.createElement("input");
cfgnameField.name = "cfgname";
cfgnameField.type = "text";
cfgnameField.value = configname;
form_ref.appendChild(cfgnameField);

var cfgdescField = document.createElement("input");
cfgdescField.name = "cfgdesc";
cfgdescField.type = "text";
cfgdescField.value = configdesc;
form_ref.appendChild(cfgdescField);

var cfgenvField = document.createElement("input");
cfgenvField.name = "cfgenv";
cfgenvField.type = "text";
cfgenvField.value = configenv;
form_ref.appendChild(cfgenvField);

var cfgfileField = document.createElement("input");
cfgenvField.name = "cfgfile";
cfgenvField.type = "text";
cfgenvField.value = absolutepath;
form_ref.appendChild(cfgfileField);

var cfgdateField = document.createElement("input");
cfgenvField.name = "updatedDate";
cfgenvField.type = "text";
cfgenvField.value = absolutepath;
form_ref.appendChild(cfgdateField);

form_ref.submit();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:43:03+00:00Added an answer on May 23, 2026 at 9:43 am

    Maybe you have the same problem seen here:

    Why can't I submit a dynamically created form in Firefox

    it basically says to append it to your document.body before submitting.

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