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Home/ Questions/Q 7278969
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T22:57:06+00:00 2026-05-28T22:57:06+00:00

I am creating a menu that opens and closes using jQuery. In simple terms,

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I am creating a menu that opens and closes using jQuery. In simple terms, it works like this:

function open_menu() {
    $(this).next('ul.sub-menu').css('display', 'block').stop(true, false).animate({
        width: '235px',
    }, 500);
}

function close_menu() {
    // close code here
}

status = 'closed'; // set the default menu status

$('a').click(function() {
    switch(status) {
        case 'closed':
            open_menu();
            break;
        case 'open':
            close_menu();
            break;
    }
}

If I take the contents of open_menu() and put it in place of open_menu() in the .click() event, every works as expected. If I use the code as show above, $(this) can not figure out that .click() fired it and the code does not run.

Is there something that I can do to have the $(this) selector negotiate what fired it while keeping it in open_menu()?

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  1. Editorial Team
    Editorial Team
    2026-05-28T22:57:07+00:00Added an answer on May 28, 2026 at 10:57 pm

    The this that you refer to in open_menu is the context of the open_menu function, not the click handler of the link. You need to do something like this:

    open_menu(this);
    
    function open_menu(that) {
        $(that).next(...
    
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