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Home/ Questions/Q 8712113
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T05:02:36+00:00 2026-06-13T05:02:36+00:00

I am creating a program in C where i have to accept an integer

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I am creating a program in C where i have to accept an integer to continue.I read some questions to use the following code but my program just goes into infinite loop soon after entering any character.Please help me

    int tnum,scancheck;
printf("Enter the number of teams(Maximum 4)\n");
scancheck = scanf("%d",&tnum);
while(scancheck != 1)
{
    printf("ERROR: Please enter numbers only\n\n");
    printf("Enter the number of teams(Maximum 4)\n");
    scancheck = scanf("%d",&tnum);  
}

I used Kirilenko’s method but my program goes into infinite loop on entering a special character such as l=

EDIT
PROBLEM HAS BEEN SOLVED.Thanks guys

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T05:02:39+00:00Added an answer on June 13, 2026 at 5:02 am

    You have to clean stdin between your calls to scanf. Otherwise the behaviour of scanf with an invalid input is to put back the character on the stream. Then, it go to an infinite loop where you read the same wrong character every iteration.

    #include <stdio.h>
    
    void clean_stdin(void) {
        int c;
        while ((c = getchar()) != '\n' && c != EOF)
            ;
    }
    
    /* ... */
    
    int ret;
    int n;
    
    do {
       ret = scanf("%d", &n);
       clean_stdin();
    } while (ret != 1);
    
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