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Home/ Questions/Q 8686429
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:50:47+00:00 2026-06-12T22:50:47+00:00

I am creating a search within my database and when I used the foreach

  • 0

I am creating a search within my database and when I used the foreach construct for my results to be echoed I’m getting “invalid argument being supplied for foreach..”. What I don’t understand is why this error is coming up because the foreach containing my errors works fine.

if (empty($errors)){
    $results = search_results($keywords);
    $results_num = count($results);

    foreach ($results as $result){
        echo '<p> <strong>', $result['TITLE'], '</strong> </p>';
    }
} else {
    foreach($errors as $error){
        echo $error, '</br>';
    }
}

The part of the search_results function that’s being focused on is this

$results = "SELECT TITLE FROM occupationalinfo WHERE $where"; 
$results_num = ($results = mysql_query($results)) ? mysql_num_rows($results): 0;

if ($results_num === 0){
    return false;
}else{
    while ($results_row = mysql_fetch_assoc($results)) {
        $returned_results[] = array(
            'title' => $results_row['TITLE']
        );      
    }
}

I am still new to programming so I understand if there is something I may have missed or just not quite get. I would greatly appreciate any tips or constructive criticism.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:50:48+00:00Added an answer on June 12, 2026 at 10:50 pm
    if ($results_num === 0){
        return false;
    }
    

    I’d bet this is executing, so it’s returning false. You cannot apply foreach to false. Perhaps you should return array(), or just check for false:

    $results = search_results($keywords);
    if ($results !== false) {
        $results_num = count($results);
    
        foreach ($results as $result){
            echo '<p> <strong>',$result['TITLE'],'</strong> </p>';
        }
    }
    
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