Question

I am creating a simple c program and output of below program should be 2 but i am getting 50 dont know why (i am newbie to c) please let me know where i am missing

#include<stdio.h>
int main(int argc, char** argv) {
   int a[4]={'1','2','2','\0'};
   printf("The value of a is %d",a[1]);
   return 0;
}

here is live output

Answer 1

You initialised the array using ascii character codes. '2' has integer value 50.

Initialise the array as

int a[4]={1,2,2,0};

if you want it to contain integers 1,2,2,0. Or

#include<stdio.h>
int main(int argc, char** argv) {
   char a[4]="121";
   printf("The value of a is %c",a[1]);
   return 0;
}

if you want an array of characters that can be treated as a string. (Note the use of the %c format specifier here.)