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Editorial Team
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Asked: 2026-05-15T06:26:49+00:00

I am creating a table to display on a web page and that table

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I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me.

First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug.

Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser.

    $query = "SELECT * FROM employees";
    $result = mysql_query($query);

    $num = mysql_num_rows($result);

    echo '<table>';

    for ($i = 0; $i < $num; $i++){
        $row = mysql_fetch_array($result);
        $id = $row['id'];
        $l_name = $row['l_name'];
        $f_name = $row['f_name'];
        $ssn = $row['ssn'];

        $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row";

        echo "<tr>";
            echo "<td class=" . $class . ">$wrap_id</td>";
            echo "<td class=" . $class . ">$wrap_l_name</td>";
            echo "<td class=" . $class . ">$wrap_f_name</td>";
            echo "<td class=" . $class . ">$wrap_ssn</td>";
        echo "</tr>";

    }

    echo '</table>';

    mysql_close($link);

}

EDIT

To answer a few questions:

@controlfreak123, I am not sure what you mean by “include (‘filename_with_php_in_it’)”. As far as the page not being called to be parsed, I think it is being called and contact is being made. I pointed out in my original question that I believe this is true because FireBug shows the code for the table, and that code is in separate PHP file, thus communication between the HTML file and the PHP file must be taking place. Here is how I am calling the PHP file from the HTML file you if you care to know:

<script language="javascript" type="text/javascript" src="/Management/Employee_Management.php?action=Edit_Employee"></script>

@Matt S, I am not getting much in the way of output, in fact I didn’t know I was getting anything at all until I looked at FireBug and saw that the PHP code (or some of it) was indeed being passed to the HTML file. The specific question is how do I get the data I want from my MySQL database and populate it into an HTML table via PHP. I can also confirm that employees does have data in it, two entries I put in for testing. I can try to put the code into its own file without the JavaScript as you suggested, but that would defeat my purpose since I want my HTML and PHP files to be separate, but I may try it just to see if the PHP code is good and to make sure the JavaScript isn’t breaking it.

@Aaron, I am not sure what you are asking (sorry). The code is meant to populate create and populate a table on an HTML page.

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1 Answer

  1. Editorial Team

    Here is a full example of what you’re looking for:

    1. pull some data from mysql using php
    2. put that data into an html table
    3. apply alternating colored rows to the table

    For the styling I cheat a little and use jquery which I find a bit easier then what you’re trying to do.

    Also, remember $row[field] is case sensitive. So $row[id] != $row[ID].

    Hope this helps:

    <html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
        <style type="text/css">
            tr.header
            {
                font-weight:bold;
            }
            tr.alt
            {
                background-color: #777777;
            }
        </style>
        <script type="text/javascript">
            $(document).ready(function(){
               $('.striped tr:even').addClass('alt');
            });
        </script>
        <title></title>
    </head>
    <body>
        <?php

            $server = mysql_connect("localhost","root", "");
            $db =  mysql_select_db("MyDatabase",$server);
            $query = mysql_query("select * from employees");
        ?>
        <table class="striped">
            <tr class="header">
                <td>Id</td>
                <td>Name</td>
                <td>Title</td>
            </tr>
            <?php
               while ($row = mysql_fetch_array($query)) {
                   echo "<tr>";
                   echo "<td>".$row[ID]."</td>";
                   echo "<td>".$row[Name]."</td>";
                   echo "<td>".$row[Title]."</td>";
                   echo "</tr>";
               }

            ?>
        </table>
    </body>
</html>

    Here’s the table code only using PHP to alternate the styles like you’re trying to do in your example:

        <table class="striped">
        <tr class="header">
            <td>Id</td>
            <td>Title</td>
            <td>Date</td>
        </tr>
        <?php
           $i = 0;
           while ($row = mysql_fetch_array($query)) {
               $class = ($i == 0) ? "" : "alt";
               echo "<tr class=\"".$class."\">";
               echo "<td>".$row[ID]."</td>";
               echo "<td>".$row[Name]."</td>";
               echo "<td>".$row[Title]."</td>";
               echo "</tr>";
               $i = ($i==0) ? 1:0;
           }

        ?>
    </table>
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