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Asked: May 11, 20262026-05-11T02:23:53+00:00 2026-05-11T02:23:53+00:00

I am creating a test program to test the functionality of program which calcultes

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I am creating a test program to test the functionality of program which calcultes CPU Utilization.

Now I want to test that program at different times when CPU utilization is 100%, 50% 0% etc.

My question how to make CPU to utilize to 100% or may be > 80%.

I think creating a while loop like will suffice

while(i++< 2000) {    cout<<' in while '<< endl;    Sleep(10); // sleep for 10 ms. } 

After running this I dont get high CPU utilization. What would be the possible solutions to make high cpu intensive??

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  1. 2026-05-11T02:23:54+00:00Added an answer on May 11, 2026 at 2:23 am

    You’re right to use a loop, but:

    • You’ve got IO
    • You’ve got a sleep

    Basically nothing in that loop is going to take very much CPU time compared with the time it’s sleeping or waiting for IO.

    To kill a CPU you need to give it just CPU stuff. The only tricky bit really is making sure the C++ compiler doesn’t optimise away the loop. Something like this should probably be okay:

    // A bit like generating a hashcode. Pretty arbitrary choice, // but simple code which would be hard for the compiler to // optimise away. int running_total = 23; for (int i=0; i < some_large_number; i++) {     running_total = 37 * running_total + i; } return running_total; 

    Note the fact that I’m returning the value out of the loop. That should stop the C++ compiler from noticing that the loop is useless (if you never used the value anywhere, the loop would have no purpose). You may want to disable inlining too, as otherwise I guess there’s a possibility that a smart compiler would notice you calling the function without using the return value, and inline it to nothing. (As Suma points out in the answer, using volatile when calling the function should disable inlining.)

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