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Home/ Questions/Q 6955527
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:44:53+00:00 2026-05-27T14:44:53+00:00

I am creating a web app using jQuery Mobile and PhoneGap. There is a

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I am creating a web app using jQuery Mobile and PhoneGap. There is a graph and if the user is using a large screen, I would like to display more points on this graph, because points are tappable and the shouldn’t be too close (physically).

For example: if someone has an iPhone, I want to display N points on the line graph. If he has an iPad, i want to display 2xN points (cause iPad has physically larger screen), but if he has some newer Android phone that is physically small like an iPhone but has a screen with many pixels (like an iPad), I want to display N points, because the points are physically small (and closer together).

So is there a way to get this data? An alternative is determining whether the device is a tablet.

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:44:53+00:00Added an answer on May 27, 2026 at 2:44 pm

    What you want is to check the device’s pixel density – measured in DPI – as @Smamatti already mentioned you control this with CSS media queries.

    Here’s an article on how to cope with varying DPIs and screen sizes, using those CSS media queries.

    UPDATE: here’s the javascript function (from the above link) that uses a trick to figure out the current device DPI:

    function getPPI(){
     // create an empty element
     var div = document.createElement("div");
     // give it an absolute size of one inch
     div.style.width="1in";
     // append it to the body
     var body = document.getElementsByTagName("body")[0];
     body.appendChild(div);
     // read the computed width
     var ppi = document.defaultView.getComputedStyle(div, null).getPropertyValue('width');
     // remove it again
     body.removeChild(div);
     // and return the value
     return parseFloat(ppi);
    }
    

    Hope this helps!

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