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Home/ Questions/Q 1077919
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:38:50+00:00 2026-05-16T21:38:50+00:00

I am creating an address book xml feed from a MySQL database, everything is

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I am creating an address book xml feed from a MySQL database, everything is working fine, but I have a section tag which gets the first letter of the surname and pops it in that tag. I only want this to display if it has changed, but for some reason my brain isn’t working this morning!

Current code:

<?php

echo "<?xml version=\"1.0\" encoding=\"UTF-8\"?>";
echo "<data>";

do {

    $char = $row_fetch["surname_add"];
    $section = $char[0];

    //if(changed???){
        echo "<section><character>".$section."</character>";
    //}
    echo "<person>";
    echo "<name>".$row_fetch["firstname_add"]." ".$row_fetch["surname_add"]."</name>";
    echo "<title>".$row_fetch["title_add"]."</title>";
    echo "</person>";

    //if(){
        echo "</section>";
    //}


} while ($row_fetch = mysql_fetch_assoc($fetch));

echo "</data>";

?>

Any help on this welcome, don’t know why I can’t think of it!

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:38:51+00:00Added an answer on May 16, 2026 at 9:38 pm

    And if you still want to generate XML manually, I suppose, something like this will work:

    $section = "NoSectionStartedYet";
    while ($row_fetch = mysql_fetch_assoc($fetch)) {
    
        $char = $row_fetch["surname_add"];
        if ($char[0] != $section)
        {
            if ($section != "NoSectionStartedYet")
            {
                echo "</section>";
            }
            $section = $char[0];
            echo "<section><character>".$section."</character>";
        }
    
        echo "<person>";
        echo "<name>".$row_fetch["firstname_add"]." ".$row_fetch["surname_add"]."</name>";
        echo "<title>".$row_fetch["title_add"]."</title>";
        echo "</person>";
    
    }
    echo "</section>";
    
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