Question

I am creating REST based APIs for an app using Tastypie with Django. The problem is default API url in Tastypie contains version info in url patterns i.e.

http://lx:3001/api/v1/vservers/?username=someuser&api_key=someapikey

I want my url to be free from API version info like this:

http://lx:3001/api/vservers/?username=someuser&api_key=someapikey

urls.py

v1_api = Api()
v1_api.api_name = ''
v1_api.register(UserResource())
...
url(r'^api/', include(v1_api.urls)),

I am overwriting api_name with an empty string still

http://lx:3001/api/vservers/?username=someuser&api_key=someapikey does not work.

How can I get rid of the version info altogether?

Thanks..

Answer 1

Subclass Api and override urls to remove all the api_name-related bits:

class MyApi(Api):
    @property
    def urls(self):
        """
        Provides URLconf details for the ``Api`` and all registered
        ``Resources`` beneath it.
        """
        pattern_list = [
            url(r"^%s$" % trailing_slash(), self.wrap_view('top_level'), name="api_top_level"),
        ]

        for name in sorted(self._registry.keys()):
            pattern_list.append((r"^/", include(self._registry[name].urls)))

        urlpatterns = self.override_urls() + patterns('',
            *pattern_list
        )
        return urlpatterns