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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:51:21+00:00 2026-05-14T00:51:21+00:00

I am curious? What high fundu logic goes behind not implementing: result+=vector1; where both

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I am curious? What high fundu logic goes behind not implementing:

result+=vector1;

where both result and vector1 are stl vectors.

Note: i know how to implement that bit, but i need to know what logic, the sages who designed STL were using when they chose not to implement this feature?

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:51:21+00:00Added an answer on May 14, 2026 at 12:51 am

    What are you expecting result to contain, the result of concatenating the original result with vector1 or an element-wise += (whatever that means for the underlying types), possibly default-initializing members if the sizes don’t match?

    And yes, this is an answer 😉 .

    Operator overloading should only be used where the meaning of the operation is unambiguous and practical for the underlying type and where it would offer a significant notational brevity over appropriately named function calls.

    Note that valarray has more operator overloads than vector due to its interface and intended use.

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