Question

I am currently listening on a port using BufferedReader like:

ServerSocket ss = new ServerSocket(2346);

Socket s = ss.accept();
BufferedReader in = new BufferedReader(new InputStreamReader(s.getInputStream()));
while(true){
    inputLine = in.readLine();
    if(inputLine==null)
       break;
}

Now I am getting all the headers and everything like:

POST /record HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: text/xml;charset=UTF-8
SOAPAction: ""
Content-Length: 1969
Host: localhost:2346
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.1 (java 1.5)

<S:Envelope xmlns:S="http://www.w3.org/2003/05/soap-envelope">...

The problem is that I need just the content of the POST request(the last line above), so is there a Java parser that could do it. And in my request to the socket I need to give an extra empty line to allow it to be read properly. Is there a solution for this?

Thanks

Answer 1

The response body is always separated by one blank line from the response header. You can either write your own parser or use a library like HttpCore http://hc.apache.org/httpcomponents-core-ga/