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Home/ Questions/Q 6918135
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:49:13+00:00 2026-05-27T09:49:13+00:00

I am currently programming a background-image using PHP with a color gradient for all

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I am currently programming a background-image using PHP with a color gradient for all browsers that do not support CSS3. I have got the following code:

<?php
header("Content-Type: image/png");
$from=array("R"=>255, "G"=>255, "B"=>255);
$to=array("R"=>170, "G"=>221, "B"=>255);

$width=500;
$height=1000;
$image=imagecreate($width, $height);
for($y=0; $y < $height; $y++)
{
    imageline($image, 0, $y, $width, $y, imagecolorallocate($image, $from["R"]-(($from["R"]-$to["R"])/$height)*$y, $from["G"]-(($from["G"]-$to["G"])/$height)*$y, $from["B"]-(($from["B"]-$to["B"])/$height)*$y));
}
imagepng($image);
?>

It seems to be so simple but I really do not know why the image is not displayed correctly. It is shown as you can see below but the gradient should be 1000px high.
The gradient that is displayed

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:49:13+00:00Added an answer on May 27, 2026 at 9:49 am

    I could solve the problem. The function “imagecolorallocate” seems to be restricted to a limited number of calls. I used “imagecolorresolve” instead and it works fine. Another option is using “imagecreatetruecolor” for creating the image. Then you can use “imagecolorallocate”.

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