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Editorial Team
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Asked: 2026-06-12T15:36:06+00:00

I am currently trying to complete a project where the specifications are to use

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I am currently trying to complete a project where the specifications are to use a search form to search through a packaging database. The database has lots of variables ranging from Sizes, names, types and meats. I need to create a search form where users can search using a number of different searches (such as searching for a lid tray that is 50 cm long).

I have spent all day trying to create some PHP code that can search for info within a test database I created. I have had numerous amounts of errors ranging from mysql_fetch_array errors, boolean errors and now currently my latest error is that my table doesn’t seem to exist. Although i can enter data into it (html and php pages where I can enter data), I don’t know what is causing this and I have started again a few times now.

Can anyone give me some idea or tips of what I am going to have to do currently? Here is just my small tests at the moment before I move onto the actual sites SQL database.

Creation of database:

 <body>
  <?php
     $con = mysql_connect("localhost", "root", "");
      if (!$con)
     {
      die('Could not connect: ' . mysql_error());
     }
      if (mysql_query("CREATE DATABASE db_test", $con))
     {
  echo "Database created";
     }
      else
    {
  echo "Error creating database: " . mysql_error();
    }


  mysql_select_db("db_test", $con);
  $sql = "CREATE TABLE Liam
   ( 
  Code varchar (30),
  Description varchar (30),
  Category varchar (30),
  CutSize varchar (30),
   )";

 mysql_query($sql, $con);
     mysql_close($con);
 ?> 
   </body>

HTML search form page:

<body>

      <form action="form.php" method="post">
        Search: <input type="text" name="term" /><br />
      <input type="submit" name="submit" value="Submit" />
      </form>

</body>

The PHP code I am using to attempt to gather info from the database
(I have rewritten this a few times, this code also displays the "table.liam doesn’t exist")

  <body>
   <?php
 $con = mysql_connect ("localhost", "root", "");
 mysql_select_db ("db_test", $con);

  if (!$con)
    { 
    die ("Could not connect: " . mysql_error());
    } 
    $sql = mysql_query("SELECT * FROM Liam WHERE Description LIKE '%term%'") or die
        (mysql_error());

       while ($row = mysql_fetch_array($sql)){
    echo 'Primary key: ' .$row['PRIMARYKEY'];
    echo '<br /> Code: ' .$row['Code'];
    echo '<br /> Description: '.$row['Description'];
    echo '<br /> Category: '.$row['Category'];
    echo '<br /> Cut Size: '.$row['CutSize']; 
  }
 
  mysql_close($con)
   ?>
     </body>
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1 Answer

  1. Editorial Team

    try this out let me know what happens.

    Form:

    <form action="form.php" method="post"> 
Search: <input type="text" name="term" /><br /> 
<input type="submit" value="Submit" /> 
</form>

    Form.php:

    $term = mysql_real_escape_string($_REQUEST['term']);    

$sql = "SELECT * FROM liam WHERE Description LIKE '%".$term."%'";
$r_query = mysql_query($sql);

while ($row = mysql_fetch_array($r_query)){ 
echo 'Primary key: ' .$row['PRIMARYKEY']; 
echo '<br /> Code: ' .$row['Code']; 
echo '<br /> Description: '.$row['Description']; 
echo '<br /> Category: '.$row['Category']; 
echo '<br /> Cut Size: '.$row['CutSize'];  
}

    Edit: Cleaned it up a little more.

    Final Cut (my test file):

    <?php
$db_hostname = 'localhost';
$db_username = 'demo';
$db_password = 'demo';
$db_database = 'demo';

// Database Connection String
$con = mysql_connect($db_hostname,$db_username,$db_password);
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db($db_database, $con);
?>

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8" />
        <title></title>
    </head>
    <body>
<form action="" method="post">  
Search: <input type="text" name="term" /><br />  
<input type="submit" value="Submit" />  
</form>  
<?php
if (!empty($_REQUEST['term'])) {

$term = mysql_real_escape_string($_REQUEST['term']);     

$sql = "SELECT * FROM liam WHERE Description LIKE '%".$term."%'"; 
$r_query = mysql_query($sql); 

while ($row = mysql_fetch_array($r_query)){  
echo 'Primary key: ' .$row['PRIMARYKEY'];  
echo '<br /> Code: ' .$row['Code'];  
echo '<br /> Description: '.$row['Description'];  
echo '<br /> Category: '.$row['Category'];  
echo '<br /> Cut Size: '.$row['CutSize'];   
}  

}
?>
    </body>
</html>
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