Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1052645
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T17:07:34+00:00 2026-05-16T17:07:34+00:00

I am currently trying to create a PHP script whereby there is already a

  • 0

I am currently trying to create a PHP script whereby there is already a login script created and the user that successfully logs into the home.php is able to view the tables of the database he is logged into.

Is there any ways of retrieving the tables using the mySQL query like “SHOW TABLES”?

Here are some of my codes:

<?php
session_start();
if($_SESSION['id'])
{
    echo "Welcome ",$_SESSION['username']."<br>";
    echo "Click here to Logout :    ".'<br><a href="logout.php">Logout</a>';
}
else
{
    echo "You don't belong here!";
}



$tableSQL = "SHOW TABLES";

$tablesoutput = mysql_query($tableSQL);

print $tablesoutput;

?>

I think my codes are wrong as there are errors showing that access is denied to the database. Does it mean that I have to reconnect to the database even though I have a session established?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T17:07:35+00:00Added an answer on May 16, 2026 at 5:07 pm

    A session only means that values stored in the $_SESSION variable are persisted across separate requests, but that’s all. It does not “log a user into the database” nor does it keep a database connection open. You’ll have to establish a database connection on every page load.

    You also need to use mysql_fetch_assoc on the result of mysql_query. A simple print won’t suffice.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 514k
  • Answers 514k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer If I understood it right, this is the code I'd… May 16, 2026 at 6:11 pm
  • Editorial Team
    Editorial Team added an answer Make that a lookbehind assertion. (?<!^src=") May 16, 2026 at 6:11 pm
  • Editorial Team
    Editorial Team added an answer I can suggest you the following code -(void)homeButtonClicked { [self.navigationController… May 16, 2026 at 6:11 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

I am currently trying to create a content uploading system and although there are
I'm currently trying to expand my PHP driven intranet site for my company. It
I am trying to make a script that lists only folders within a folder.
I'm currently trying to develop a method to get a overview of all my
Good Afternoon, I'm currently trying to build something incredibly simple inside of the Google
I am trying to create an XML file, but the XML file needs to
I have a calendar application, and in that calendar application, there is a mini
I am currently trying to find a good solution for what to do with
i'm trying to create a portfolio website using wordpress, each post has view costum
I'm trying to dynamically create an object of a certain type in a LINQ-to-XML

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.