Question

I am currently trying to make my Ajax to post some informations from a HTML form, into a PHP form.

Well, now I have made difference codes which should be printed out at the “ajax.comment.php” page, telling what happened.

Like if it went successfully or not.

I now want to make my ajax, check what the printed html was.
And then handle on that.. Like if (Printed HTML == “1”) {Then do something}.

How can I do that?

My following javascript is:

var name = document.comment.name.value;
var email = document.comment.email.value;
var website = document.comment.website.value;
var message = document.comment.message.value;
var id = document.comment.id.value;
$.ajax({
      type: "POST",
      url: "ajax.addcomment.php",
      data: "name="+name+"&email="+email+"&website="+website+"&message="+message+"&id="+id,
      beforeSend: function() {
        // Action before sending data
      },
      success: function(returned_html) {
        // Action after sending data, where the returned_html var is the returned html text by the php
      }
  });

Answer 1

Inside your success function, try this:

success: function(returned_html) {
    var the_result = $.trim(returned_html);
    if(the_result == '1')
    {
        // Do whatever you wanted here.
    }
    else
    {
        // Do something else here...
    }
}