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Asked: May 11, 20262026-05-11T14:05:27+00:00 2026-05-11T14:05:27+00:00

I am currently using the directory walker from Here import os class DirectoryWalker: #

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I am currently using the directory walker from Here

import os class DirectoryWalker: # a forward iterator that traverses a directory tree  def __init__(self, directory):     self.stack = [directory]     self.files = []     self.index = 0  def __getitem__(self, index):     while 1:         try:             file = self.files[self.index]             self.index = self.index + 1         except IndexError:             # pop next directory from stack             self.directory = self.stack.pop()             self.files = os.listdir(self.directory)             self.index = 0         else:             # got a filename             fullname = os.path.join(self.directory, file)             if os.path.isdir(fullname) and not os.path.islink(fullname):                 self.stack.append(fullname)             return fullname  for file in DirectoryWalker(os.path.abspath('.')):     print file 

This minor change allows you to have the full path within the file.

Can anyone help me how to find just the filename as well using this? I need both the full path, and just the filename.

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  1. 2026-05-11T14:05:28+00:00Added an answer on May 11, 2026 at 2:05 pm

    Rather than using ‘.’ as your directory, refer to its absolute path:

    for file in DirectoryWalker(os.path.abspath('.')):     print file 

    Also, I’d recommend using a word other than ‘file’, because it means something in the python language. Not a keyword, though so it still runs.

    As an aside, when dealing with filenames, I find the os.path module to be incredibly useful – I’d recommend having a look through that, especially

    os.path.normpath 

    Normalises paths (gets rid of redundant ‘.’s and ‘theFolderYouWereJustIn/../’s)

    os.path.join 

    Joins two paths

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