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Editorial Team
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Asked: 2026-06-15T08:58:28+00:00

I am currently using the following code in my Product model to read and

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I am currently using the following code in my Product model to read and save the og:images of retail sites. 

def photo_from_url(url)
  if !Nokogiri::HTML(open(url)).css("meta[property='og:image']").blank?
    photo_url = Nokogiri::HTML(open(url)).css("meta[property='og:image']").first.attributes["content"]
    self.photo = URI.parse(photo_url)
    self.save
  end
end

While this works on most pages, there are some og:images that return bad URI(is not URI?)
An example of such a link is the following link format at H&M’s retail site.

http://lp.hm.com/hmprod?set=source[/model/2012/K71 05701 95313 06 0043 0.jpg],rotate[],width[],height[],x[],y[],type[STILL_LIFE_FRONT]&call=url[file:/product/facebook]

Obviously, this isn’t a pretty link (even StackOverflow’s Markdown parser can’t tell that it’s a link…), but it does actually work when pasted directly into a browser.

What can I do to correctly read a link like this?

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1 Answer

  1. Editorial Team

    Whoa, that looks like a nasty URL. Nice URL scheme notwithstanding, I suggest you simply escape your URLs using URI::Escape:

    irb(main):001:0> url = "http://lp.hm.com/hmprod?set=source[/model/2012/K71 05701 95313 06 0043 0.jpg],rotate[],width[],height[],x[],y[],type[STILL_LIFE_FRONT]&call=url[file:/product/facebook]"
=> "http://lp.hm.com/hmprod?set=source[/model/2012/K71 05701 95313 06 0043 0.jpg],rotate[],width[],height[],x[],y[],type[STILL_LIFE_FRONT]&call=url[file:/product/facebook]"
irb(main):002:0> uri = URI.escape url
=> "http://lp.hm.com/hmprod?set=source[/model/2012/K71%2005701%2095313%2006%200043%200.jpg],rotate[],width[],height[],x[],y[],type[STILL_LIFE_FRONT]&call=url[file:/product/facebook]"
irb(main):003:0> URI(uri)
=> #<URI::HTTP:0x000000024321d0 URL:http://lp.hm.com/hmprod?set=source[/model/2012/K71%2005701%2095313%2006%200043%200.jpg],rotate[],width[],height[],x[],y[],type[STILL_LIFE_FRONT]&call=url[file:/product/facebook]>
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