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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T10:24:35+00:00 2026-06-07T10:24:35+00:00

I am currently using the following code: text = a, 1; b, 2 temp

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I am currently using the following code:

text = "a, 1; b, 2"
temp = []
text.gsub(/\s+/, "").split(";").each {|x| temp << x.split(",")}
temp # => [["a","1"],["b","2"]]

I’m wondering if there is slick way to get this done all in one line without the extra temp = [] line? How would one join the result of each block execution into an array?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-07T10:24:37+00:00Added an answer on June 7, 2026 at 10:24 am

    The Enumerable module is a must-read for any Ruby novice. Use Enumerable#map instead:

    text.gsub(/\s+/, "").split(";").map { |x| x.split(",") }
    #=> [["a", "1"], ["b", "2"]]
    

    It appears you’re not familiar with the functional programming principles, here it’s a link it may help you (specifically: see this). Every time you write a each think if there is some alternative (it’s ok to do a side-effect like writing a file, but it’s usually a bad idea to update a variable).

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