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Home/ Questions/Q 8962621
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:10:09+00:00 2026-06-15T16:10:09+00:00

I am currently working on a C# project and I need add data to

  • 0

I am currently working on a C# project and I need add data to a custom List array. I then later on need to enumerate through the list, finding a particular record and then modify the data. However, I am getting an error within Visual Studio

Cannot modify the return value of System.Collections.Generic.List<EmailServer.ThreadCheck>.this[int] because it is not a variable. 

Below is the code that initialises the List Array

static List<ThreadCheck> threadKick = new List<ThreadCheck>();

Below is how I am adding data to the List array

public static void addThread(ILibraryInterface library, int threadID, string threadName)
{
    if (Watchdog.library == null)
    {
        Watchdog.library = library;
    }
    long currentEpochTime = library.convertDateTimeToEpoch(DateTime.Now);
    threadKick.Add(new ThreadCheck()
    {
        threadName = threadName,
        threadID = threadID,
        epochTimeStamp = currentEpochTime
    });
    library.logging(classDetails + MethodInfo.GetCurrentMethod().Name, string.Format("Thread ID: {0} has been added to watchdog for {1}",
        threadID, threadName));
}

Below is the code where I am trying to modify the data within the list

public static void kickThread(int threadId)
{
    lock (threadKick)
    {
        for (int i = 0; i < threadKick.Count; i++)
        {
            if (threadKick[i].threadID == threadId)
            {
                threadKick[i].epochTimeStamp = library.convertDateTimeToEpoch(DateTime.Now);
                break;
            }
        }
    }
}

How can I modify the content of the list array without getting the error as above?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:10:10+00:00Added an answer on June 15, 2026 at 4:10 pm

    Welcome to the wonderful world of evil mutable structs!

    Change ThreadCheck to a class and everything will work fine.

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