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Home/ Questions/Q 8779143
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T19:42:40+00:00 2026-06-13T19:42:40+00:00

I am currently working on a project, having an embedded system sending data to

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I am currently working on a project, having an embedded system sending data to a PC via radio. The packets get a crc16 checksum at the end and it’s calculated based on this algorithm:

uint16_t crc16 (const uint8_t * buffer, uint32_t size) {
    uint16_t crc = 0xFFFF;

    if (buffer && size)
        while (size--)
        {
            crc = (crc >> 8) | (crc << 8);
            crc ^= *buffer++;
            crc ^= ((unsigned char) crc) >> 4;
            crc ^= crc << 12;
            crc ^= (crc & 0xFF) << 5;
        }

    return crc;
}

Now I am looking for an equivalent in Java. I already found a good one here:
http://introcs.cs.princeton.edu/java/51data/CRC16CCITT.java.html

public class CRC16CCITT { 

    public static void main(String[] args) { 
        int crc = 0xFFFF;          // initial value
        int polynomial = 0x1021;   // 0001 0000 0010 0001  (0, 5, 12) 

        // byte[] testBytes = "123456789".getBytes("ASCII");

        byte[] bytes = args[0].getBytes();

        for (byte b : bytes) {
            for (int i = 0; i < 8; i++) {
                boolean bit = ((b   >> (7-i) & 1) == 1);
                boolean c15 = ((crc >> 15    & 1) == 1);
                crc <<= 1;
                if (c15 ^ bit) crc ^= polynomial;
             }
        }

        crc &= 0xffff;
        System.out.println("CRC16-CCITT = " + Integer.toHexString(crc));
    }

}

But this doesnt work with my C Code.

Is anybody able to deliver an adaption or solution for a C and Java equivalent algorithm?
Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T19:42:41+00:00Added an answer on June 13, 2026 at 7:42 pm

    The major difference between java and c in this case is the fact in c you use unsigned numbers and java has only signed numbers. While you can implement the same algorithm with signed numbers, you have to be aware of the fact the sign bit is carried over on shift operations, requiring an extra “and”.

    This is my implementation:

    static int crc16(final byte[] buffer) {
        int crc = 0xFFFF;
    
        for (int j = 0; j < buffer.length ; j++) {
            crc = ((crc  >>> 8) | (crc  << 8) )& 0xffff;
            crc ^= (buffer[j] & 0xff);//byte to int, trunc sign
            crc ^= ((crc & 0xff) >> 4);
            crc ^= (crc << 12) & 0xffff;
            crc ^= ((crc & 0xFF) << 5) & 0xffff;
        }
        crc &= 0xffff;
        return crc;
    
    }
    
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