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Home/ Questions/Q 8926451
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T07:58:33+00:00 2026-06-15T07:58:33+00:00

I am currently working on a project to convert VB6 code to PHP and

  • 0

I am currently working on a project to convert VB6 code to PHP and I need some help. I would like to know if my conversion of my checksum function is correct because the value that I am getting is not accurate at all.

VB6 Code:

Function CheckSum(St As String) As Long
 Dim A As Long, B As Long
 For A = 1 To Len(St)
     B = B + Asc(Mid$(St, A, 1))
 Next A
 CheckSum = B
End Function

TO

PHP Code:

Function CheckSum($st)
{

For($a=0; $a<Count($st); $a++)
{
$B = $B + SubStr($st,$a,1);
}
return $B;
}

The whole PHP code:

Function CheckSum($st)
{

For($a=0; $a<Count($st); $a++)
{
$B = $B + SubStr($st,$a,1);
}
return $B;
}

Function DoubleChar($num)
{
$DoubleChar = Chr(IntVal($num / 256)) + Chr($num % 256);
Return $DoubleChar;
}

$host = '127.0.0.1'; 
$port = 7973; 
$waitTimeoutInSeconds = 1; 
if($fp = fsockopen($host,$port,$errCode,$errStr,$waitTimeoutInSeconds))
{   
$getplayers = DoubleChar(Chr(35)) + Chr(CheckSum(Chr(35)) * 20 % 194) + Chr(0) + Chr(35);
if(fwrite($fp, $getplayers)):
while (!feof($fp)) 
{
    $buffer = fread($fp, 256);
echo IntVal($buffer);
}   
endif;
} else {
echo "ERROR: $errno - $errstr<br />\n";
} 
fclose($fp);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T07:58:34+00:00Added an answer on June 15, 2026 at 7:58 am

    The VisualBasic checksum code you posted operates over each character of the string st and transforms it to its Ansi code equivalent (the Asc() function). Moreover the VB code uses the Len() function to operate on the string whereas your PHP code is using the count() function, which operates over an array.

    In order to achieve the equivalent result in PHP you’ll need to use a similar function such as ord() with strlen() so your checksum function would look something like:

    function CheckSum($st)
    {
        for($a=0; $a<strlen($st); $a++)
        {
            $B = $B + ord(substr($st,$a, 1));
        }
        return $B;
    }
    
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