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Home/ Questions/Q 8496797
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:57:01+00:00 2026-06-10T23:57:01+00:00

I am currently working with radio buttons to display an image when clicked on

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I am currently working with radio buttons to display an image when clicked on with the help of javascript. The problem is that I am not getting result displayed when clicking a radio button. The code below shows that i am using a function and then triggering the even when click. Is there something the code is missing? or Is there a better approach to this? This an Example

Thank you

Javascript

<script>
    function check_value() {
        function check_value(fieldvalue) {
            switch (fieldvalue) {
            case 1:
                document.getElementById("imagedest").innerHTML = "<img src='images/bike1.jpg'>";
                break;
            case 2:
                document.getElementById("imagedest").innerHTML = "<img src='images/bike2.jpg'>";
                break;
            case 3:
                document.getElementById("imagedest").innerHTML = "<img src='images/bike3.jpg'>";
                break;
            }
        }
</script>

HTML

<form name="builder">
  <input type="radio" name="field" value="one" onclick='check_value(1)'/> KAWASAKI KX 450F<br />
  <input type="radio" name="field" value="two" onclick='check_value(2)'/> 2010 Yamaha Road Star S<br />
  <input type="radio" name="field" value="three" onclick='check_value(3)'/> Aprilia RSV4<br />
</form>


<div id="imagedest"></div>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:57:02+00:00Added an answer on June 10, 2026 at 11:57 pm

    What is the purpose of the extra function check_value() { preceding the code? It seems its purpose is to stop your code from working and therefore prompt you to ask this question.

    Remove it, and all will be well.

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