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Home/ Questions/Q 837463
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T05:08:41+00:00 2026-05-15T05:08:41+00:00

I am currently writing my own shell program. This simple shell can just execute

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I am currently writing my own shell program. This simple shell can just execute commands.

When executing commands like vi or calc which require input from the terminal , the command is getting executed and is waiting for the input from the user. But I am unable to give any input on the screen.

How should the input be handled during the fork and exec.

Here is the piece of code which is executing commands:

    if((pid = fork()) < 0)
    {
            perror("Fork failed");
            exit(errno);
    }
    if(pid == 0)
    {
            // Child process
            if(execvp(arguments[0], arguments) == -1)
            {
                    child_status = errno;
                    switch(child_status)
                    {
                            case ENOENT:
                                    printf(" command not found \n");
                                    break;
                    }
                    exit(errno);
            }
    }
    else
    {
            // parent process
            int wait_stat;
            if(waitpid(pid , &wait_stat, WNOHANG) == -1)
            {
                    printf(" waitpid failed \n");
                    return;
            }
    }

}
~

Thanks,

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:08:41+00:00Added an answer on May 15, 2026 at 5:08 am

    The WNOHANG is causing the parent process not to wait and therefore (depending on platform) the child process will be detached from terminal IO or die.

    Remove the WNOHANG.

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