Question

I am debugging a PHP application that handles image resources. I would like to see the output ($dst_image as per the PHP manual’s jargon), but the code is not in a place that I could simply output it to the browser. Would the best debugging procedure be to write $dst_image to a file, and to load that file in the browser? Any other ideas?

Thanks.

Answer 1

See Example #1 and #2, imagejpeg will output the jpeg data.

You need to do few tings:

1. set headers for image header('Content-Type: image/jpeg');
2. output your image data
3. Make sure you are not outputting any data except the image

At the end you should end up with something like this:

<?php

// Get new dimensions
// Resample
// etc...

// set header so browser can render image properly
header('Content-Type: image/jpeg');

// Output
imagejpeg($image, null, xxx);
// [or] 
echo file_get_contents($pathToJpgImage);

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If you find your self in a situation where current request outputs data and you cannot output image… You can inject the base64 encoded image data into the HTML by using <img src="data:image/jpeg;base64,..." />. See php documentation on base64_encode for images.