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Home/ Questions/Q 7784893
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T20:10:06+00:00 2026-06-01T20:10:06+00:00

I am defining this function in one of my classes: public function onUse():void {};

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I am defining this function in one of my classes:

public function onUse():void {};

Then in another of my classes (let’s call it “class2”), I create a object of this class, and then want to override this function with another one. After some Google-Fu, I have found this, and used it…

button.onUse {
    variable = value;
}

…but it executes instantly, and not when onUse() is called – which seems to be an empty function, always.

I didn’t find anything more than that – I tried a few things myself, like specifying a function inside class2 and using button.onUse = function();, but it always throws errors.

Can anyone tell me whether what I am trying to do is actually possible, and if it is, how can I do it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T20:10:07+00:00Added an answer on June 1, 2026 at 8:10 pm

    You can only override functions when you are extending the class:

    public class A {
        public function foo():void {
            doStuff();
        }
    }
    
    public class B extends A {
        override public function foo():void {
            doOtherStuff();
        }
    }
    
    var n:A = new A(); 
    n.foo(); // => calls doStuff();
    
    var o:B = new B();
    o.foo(); // => calls doOtherStuff();
    

    Hence, assigning a different function to a class method of an instance is not possible at runtime.

    You can, however, let your original class contain a field of type Function, and then simply assign a different closure to it.

    public class A {
        public var foo:Function;
    }
    
    var n:A = new A();
    n.foo = function ():void { 
        doStuff();
    };
    n.foo(); // => calls doStuff();
    
    var o:A = new A();
    o.foo = function ():void {
        doOtherStuff();
    }
    o.foo(); // => calls doOtherStuff();
    
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