Question

I am developing a module in website to save and retrieve friend list. I am using Zend Framework and for DB handling I am using Doctrine(ORM).

There are two models:

1) users that stores all the users
2) my_friends that stores the friend list (that is reference table with M:M relation of user)

the structure of my_friends is following

---

…id……….user_id…………friend_id……..approved….
…10………20 ………………25……………….1……….
…10………21 ………………25……………….1……….
…10………22 ………………30……………….1……….
…10………25 ………………30……………….1……….

---

The Doctrine query to retrieve friend list id following

$friends = Doctrine_Query::create()->from('my_friends as mf')
                                 ->leftJoin('mf.users as friend')
                                 ->where("mf.user_id = 25")
                                 ->andWhere("mf.approved = 1");  

Suppose I am viewing the user no.- 25.
With this query I am only getting the user no.- 30.
where as user no.- 25 is also approved friend of user no.- 20 and 21.
Please guide me, what should be the query to find all friend and is there any need to change the DB structure.

YAML
Member:
columns:

id:
  primary: true
  type: integer
  notnull: true
  autoincrement: true
userName:
  unique: true
  type: string(255)
Address_id:
  type: integer(4)
MemberPhoto_id:
  type: integer
 relations:
address:
  class: Address
  local: Address_id
  foreign: id
memberPhotos:
  class: MemberThumbnail
  foreignAlias: member
  local: MemberPhoto_id
  foreign: id

refPeeps:
columns:
id:
  primary: true
  unique: true
  type: integer
  autoincrement: true
Member_id:
  type: integer
  notnull: true
Peep_id:
  type: integer
  notnull: true
relations:
Member:
  local: Member_id
  foreign: id
Member:
  local: Peep_id
  foreign: id

Answer 1

– Hello Amrit.

– I think you need to fetch data with two query. According to me you have to follow these steps

1. First get all data with join query corresponding to friend_id.
2. And second time you apply simple query for user_id and get data.
3. And then fetch data corresponding to the second query.