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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:57:27+00:00 2026-05-25T18:57:27+00:00

I am developing in Cocoa / Xcode and have an int * array containing

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I am developing in Cocoa / Xcode and have an int * array containing values.
When I want to use memcpy to shift values in the array, it transfers only 0s.

e.g.

  • Array contains values as 1 2 3 4
  • memcpy(array,array+2*sizeof(int),2*sizeof(int));

result: 0,0,3,4

Is there a better alternative to memcpy, or something I am doing wrong ?

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:57:27+00:00Added an answer on May 25, 2026 at 6:57 pm

    I think the right way to do what you want is:

    memcpy(array, array + 2, 2*sizeof(int));
    

    That’s because in the 2nd argument of memcpy pointer arithmetic is being done, and anything that’s being added to “array” pointer is considered as being a multiple of an integer’s size. So in this case saying “array + 2” means “the integer pointer `array’ plus two times the size of an integer”.

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