Question

I am developing MVC application and using razor syntax.

In this application I am giving comment facility.

I have added a partial view, which loads the comment/Records from DB.

In below image, we can see the comment box which is called run-time for employee index view.

problem is, when user delete comment, its get deleted from DB but how to remove it from the screen without redirect to any page ?

I wan to remove that deleted comment div tag smoothly…

Please see the image…

my code is…

@model  IEnumerable<CRMEntities.Comment>

@{


     <div class="ParentBlock">


    @foreach (var item in Model)
    {
        <div class="OwnerClass" id="OwnerName" data-comment-id="@item.Id">


         <span class="EmpName"> @Html.ActionLink(item.Owner.FullName, "Details", "EMployee", new { id = item.OwnerId }, new { @style = "color:#1A6690;" })</span>

           @Html.DisplayFor(ModelItem => item.CommentDateTime)

          <span class="EmpName"><button type="button" class="deleteComment">Delete</button></span>



        <p class="CommentP">
           @Html.DisplayFor(ModelItem => item.CommentText)
        </p>

        <br />
            <a class="Delete222" style="cursor:move;display:none;">DeleteNew</a>
        <br />

     </div>

    }


     <p class="p12">

      </p>



</div>

      <p id="ClassPara" class="ShowComments" onclick="chkToggle()">Show All Comments</p>

}


   @Html.TextArea("Comment", "", 5, 80, "asdsd")


    <input type="button" value="Add Comment" id="AddCommentButton"/>                         
    <input type="button" value="Clear" onclick="clearText()"/>                    

    <br />


</body>
</html>



<script src="../../Scripts/jquery.js" type="text/javascript"></script>
<script type="text/javascript">
    $(document).ready(function () {
        $(".deleteComment").click(function () {
            alert("asd");
            var commentBlock = $(this).parent('.OwnerClass');
            commentBlock.hide('slow')

     });
    });


    $(document).ready(function () {

        $('.OwnerClass').hover(function () {
            $('.Delete222', this).show();
        }, function () {
            $('.Delete222').hide();


        });

    });

</script>

Answer 1

Instead of generating action link, place there button or . Bind JavaScript function to click event on this button, in this function make ajax call to action that deletes comment from db and use Jquery to hide proper div.

<span class="EmpName"><button type="button" class="deleteComment">Delete</button></span>

JavaScript:

$('.deleteComment').click(function () 

        {
            var commentBlock = $(this).parent('.ParentBlock');
            $.ajax({

                type: 'post',
                url: '/Comment/DeleteComment',
                dataType: 'json',
                data:
                { 

                 commentId: getCommentId(commentBlock )

                },
                success: function (data) {

                    commentBlock.hide('slow')

                }

            });
        });

UPDATE:

Update due to question update and comments below this answer:

$(document).ready(function () {
    $(".deleteComment").click(function () {

        var commentBlock = $(this).parent('.OwnerClass');

        $.ajax({
            type: 'post',
            url: '/Comment/DeleteComment',
            dataType: 'json',
            data:
            { 

             commentId: commentBlock.attr('data-comment-id')

            },
            success: function (data) {

                commentBlock.hide('slow')

            }

        });

 });
});