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Home/ Questions/Q 8946599
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T12:33:43+00:00 2026-06-15T12:33:43+00:00

I am displaying the images through the Apache server. When I click on each

  • 0

I am displaying the images through the Apache server.
When I click on each image it should open download.php?fiel=file_name.jpg and download the image to the system.

This is the code for Image Display

  <?php
 $files = glob("Image/"."*.*");
 for ($i=0; $i<count($files); $i++)
{
$num = $files[$i];
echo $num."<br>";
echo '<img src="'.$num.'" alt="Here should be image" width="256" height="192" >'."<br/>";
}
?>

I used the following code to download the Image (i.e download.php file).

 <?php
 $file = $_GET['file'];
  header("Content-type: image");
 header("Content-disposition: attachment; filename= ".$file."");
 readfile($file);
 ?> 

How to achieve this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T12:33:44+00:00Added an answer on June 15, 2026 at 12:33 pm

    You mean something like this? :

    <?php
    $files = glob("Image/"."*.*");
    $countFiles = count($files); //Don't do calculations in your loop, this is really slow
    
    for ($i=0; $i<$countFiles; $i++)
    {
        $num = $files[$i];
    
        echo '<a href="download.php?file=' . $files[$i] . '"><img src="'.$num.'" alt="Here should be image" width="256" height="192" ></a><br/>';
    }
    ?>
    
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