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Home/ Questions/Q 6786169
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T17:12:49+00:00 2026-05-26T17:12:49+00:00

i am doing a project in android. i am a begineer in android also.

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i am doing a project in android. i am a begineer in android also. in my android application i am using php as my webservice provider. in my php code for the authentication i am check the user vaidity and return string 1 or 0. In android application i am get the string. but when i check it in a if condition it fails. is it due to any charset compatablity issue.

in php code

.....
if($auth) {
 echo '1';
}
else {
 echo '0';
}

in android

//get the code and saved in to string loginStatus;
if(loginStatus == "1") {
 //not getting into this part if the loginStatus is 1;
}
else {
 //getting into this part
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T17:12:50+00:00Added an answer on May 26, 2026 at 5:12 pm

    The == operator checks to see if two string references point to exactly the same string instance. So even if you have two strings that both have the value "1" the == operator can still return false.

    To compare the strings character-by-character use String.equals:

    if (loginStatus.equals("1")) {
    

    To see the difference between == and equals see this simplified example:

    String a = new String("1");
    String b = new String("1");
    System.out.println("a == b: " + (a == b));
    System.out.println("a.equals(b): " + a.equals(b));
    

    Result:

    a == b: false
    a.equals(b): true
    

    See this code running online: ideone


    Note: if loginStatus can be null you also need to check for that too, or else reverse the order of the strings so that the constant string is first:

    if (loginStatus != null && loginStatus.equals("1")) {
    

    Or:

    if ("1".equals(loginStatus)) {
    
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