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Home/ Questions/Q 7553941
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T11:12:04+00:00 2026-05-30T11:12:04+00:00

I am doing a project with Qt where in invoke method runs on a

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I am doing a project with Qt where in invoke method runs on a seperate thread and called from main thread.
If I pass a QByteArray as const it builds and runs.
However if I remove the const it builds but terminates when I try to run it,
and throws an assert Q_ASSERT(b).

Why is it getting terminated?

I have to append some data into QByteArray.

const bool b = QMetaObject::invokeMethod(m_thread, "calculateSpectrum",
                              Qt::AutoConnection,
                              Q_ARG(QByteArray, buffer),
                              Q_ARG(int, format.frequency()),
                              Q_ARG(int, bytesPerSample),
                              Q_ARG(qint64, dataLength));
    Q_ASSERT(b);
    Q_UNUSED(b) // suppress warnings in release builds
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T11:12:06+00:00Added an answer on May 30, 2026 at 11:12 am

    basically the signature of QMetaobject::invokemethod is…

    bool    invokeMethod ( QObject * obj, const char * member, Qt::ConnectionType type, QGenericReturnArgument ret, QGenericArgument val0 = QGenericArgument( 0 ), QGenericArgument val1 = QGenericArgument(), QGenericArgument val2 = QGenericArgument(), QGenericArgument val3 = QGenericArgument(), QGenericArgument val4 = QGenericArgument(), QGenericArgument val5 = QGenericArgument(), QGenericArgument val6 = QGenericArgument(), QGenericArgument val7 = QGenericArgument(), QGenericArgument val8 = QGenericArgument(), QGenericArgument val9 = QGenericArgument() );
    

    now in this we are using the Q_ARG macro whose syntax is..

    QGenericArgument    Q_ARG ( Type, const Type & value )
    

    which requires a const parameter.

    Now when u remove this const parameter the condition becomes false and it will throw an assert at runtime.

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