Question

I am doing an exam paper for revision. It’s not a particular question I want help with, but I am unsure to why the program is outputting incorrectly when certain data is entered.

def Binary(Hex):
    Result = ''
    ErrorFound = False
    BinaryEquivalent = ''
    EmptyInput=""
    for ThisHexDigit in Hex:
        if ThisHexDigit in ['1','2','3','4','5','6','7','8','9','0','A','B','C','D','E','F']:
            if ThisHexDigit == '0': BinaryEquivalent = '0'
            elif ThisHexDigit == '1': BinaryEquivalent = '1'
            elif ThisHexDigit == '2': BinaryEquivalent = '2'
            elif ThisHexDigit == '3': BinaryEquivalent = '3'
            elif ThisHexDigit == '4': BinaryEquivalent = '4'
            elif ThisHexDigit == '5': BinaryEquivalent = '5'
            elif ThisHexDigit == '6': BinaryEquivalent = '6'
            elif ThisHexDigit == '7': BinaryEquivalent = '7'
            elif ThisHexDigit == '8': BinaryEquivalent = '8'
            elif ThisHexDigit == '9': BinaryEquivalent = '9'
            elif ThisHexDigit == 'A': BinaryEquivalent = '10'
            elif ThisHexDigit == 'B': BinaryEquivalent = '11'
            elif ThisHexDigit == 'C': BinaryEquivalent = '12'
            elif ThisHexDigit == 'D': BinaryEquivalent = '13'
            elif ThisHexDigit == 'E': BinaryEquivalent = '14'
            elif ThisHexDigit == 'F': BinaryEquivalent = '15'
            Result = Result + BinaryEquivalent
        elif ErrorFound == True:
            print('You have made a mistake')
        elif Hex==EmptyInput:
            print('Empty input, try again.')

    return Result

Yes, I know this is an over-complicated piece of code but it is in the exam paper so I have to use it. It came like that, except that all the BinaryEquivalent strings were BinaryEquivalent = '' instead of having numbers inside.

The problem is when I enter two characters when the program is displaying. For example, entering “BBB” will output 11, as will ‘BBBBBB’.

Answer 1

You should put return statement out of the for cycle.