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Home/ Questions/Q 1114039
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T02:56:55+00:00 2026-05-17T02:56:55+00:00

I am doing an xslt transform inside my c# program. When I run the

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I am doing an xslt transform inside my c# program. When I run the xslt on its own it outputs just fine, but when I run it from within my c# program it always leaves off the:

<?xml version="1.0" encoding="UTF-8"?>

At the top of the resulting xml document. My XSLT file looks like:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     xmlns:hd="http://www.hotdocs.com/schemas/component_library/2009"
     xmlns:xsd="http://www.w3.org/2001/XMLSchema"
     xmlns:xml="http://www.w3.org/XML/1998/namespace">

  <xsl:output method="xml" omit-xml-declaration="no" version="1.0" encoding="UTF-8"/>

  <xsl:template match="/xsd:schema">
     <hd:componentLibrary xmlns:hd="something" version="10">
     </hd:componentLibrary>
  </xsl:template>
  <xsl:template match="text()" />
</xsl:stylesheet>

I am running the xslt in my c# program like this:

XPathDocument myXPathDoc = new XPathDocument(PathToXMLDocument);
XslCompiledTransform myXslTrans = new XslCompiledTransform();
myXslTrans.Load(PathToXSLTDocument);
XmlTextWriter myWriter = new XmlTextWriter(PathToOutputLocation, null);
myXslTrans.Transform(myXPathDoc,null,myWriter);
myWriter.Close();

I have tried the xslt document without the xsl:output line, but that does not seem to help.

How can i get the ?xml tag at the top of my outputted xml file?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-17T02:56:56+00:00Added an answer on May 17, 2026 at 2:56 am

    XmlTextWriter is a bit outdated. I recommend you switch to XmlWriter.Create.

    Then you can specify OmitXmlDeclaration = false in the XmlWriterSettings.

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