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Home/ Questions/Q 6807355
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:49:19+00:00 2026-05-26T19:49:19+00:00

I am doing C++ multithread programming. I use mutex to read and write a

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I am doing C++ multithread programming. I use mutex to read and write a queue in order to avoid deadlock. Currently, I only launch 1 thread for

    pthread_mutex_lock(&the_mutex);

But, in GDB, my code is frozen here, it is pending.

Why ? there is only one thread !!!

thanks

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:49:20+00:00Added an answer on May 26, 2026 at 7:49 pm

    From the pthread_mutex_lock() manual page:

    If the mutex type is PTHREAD_MUTEX_NORMAL, deadlock detection shall
    not be provided. Attempting to relock the mutex causes deadlock. If a
    thread attempts to unlock a mutex that it has not locked or a mutex
    which is unlocked, undefined behavior results.

    If the mutex type is PTHREAD_MUTEX_DEFAULT, attempting to recursively
    lock the mutex results in undefined behavior. Attempting to unlock the
    mutex if it was not locked by the calling thread results in undefined
    behavior. Attempting to unlock the mutex if it is not locked results
    in undefined behavior.

    Bottom line: it’s perfectly possible to cause a deadlock with only one thread if you try to lock a mutex that is already locked.

    In case you are wondering, on Linux PTHREAD_MUTEX_DEFAULT is usually a synonym of PTHREAD_MUTEX_NORMAL, which in turn is what is used in the default mutex initializer.

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