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Editorial Team
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Asked: 2026-06-11T19:03:22+00:00

I am doing questionnaire on php, I am new to php. When I try

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I am doing questionnaire on php, I am new to php. When I try to show the answers, it only shows the first two questions. After the two questions, answers are not shown. I have attached the source here.

Please use the following link to view the page.
http://itsupportsrilanka.com/uaquiz/quiz.php

<body>

<form action="test.php" method="POST">


   <?php
            $result = select("SELECT * FROM questions ");
            //$row = mysql_fetch_array($result);


        ?>
<?php
$i=1;
while($row = mysql_fetch_array($result))
{
?>
<table width="581" height="299" border="1">
<tr>
<td>Union Assurance Questionnaire</td>
</tr>
<tr>
<td><?php echo $i.'.' .$row['questions']; ?>
<?php $i++; ?>
</td>
</tr>
<tr>
<td>
<?php $qId=$row['question_id'];

$result1=select("SELECT * FROM answers WHERE questionId='$qId' ORDER BY RAND()");
while($row1=mysql_fetch_array($result1)){

    ?>
    <input type="radio" name="answers" value="<?php echo $row1['answers'];?>" / ><?php echo $row1['answers']; ?><br/>


<?php 
} ?>
&nbsp;</td>
</tr>
<tr>
<td>&nbsp;</td>
</tr>
</table>
<?php
}
?>
</form>
</body>

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1 Answer

  1. Editorial Team

    Replace 

    $result = select("SELECT * FROM questions "); with $result = mysql_query("SELECT * FROM questions ");

    and 

    $result1=select("SELECT * FROM answers WHERE questionId='$qId' ORDER BY RAND()"); with 
$result1=mysql_query("SELECT * FROM answers WHERE questionId='$qId' ORDER BY RAND()");

    and try again

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