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Home/ Questions/Q 3693690
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T04:24:24+00:00 2026-05-19T04:24:24+00:00

I am doing some study on arrays, and I am trying to resolve how

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I am doing some study on arrays, and I am trying to resolve how to store the values of a foreach loop into an array which I can then print_r().

My script works fine with the exception of the $array = foreach()... And as you can see I called return; to return the results to the $array variable, but I am getting a parse error.

Here is my code so far:

<?php

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
  <input type="radio" name="DataNameOne" value="Value 1">
  <input type="radio" name="DataNameTwo" value="Value 2">
  <input type="radio" name="DataNameThree" value="Value 3">
  <input type="submit" />
</form>
<?php

$array = foreach ($_POST as $key=>$value) {
    if (stristr($key, "section")) {
        $section = $value;
        $section_name = $key;
        return;
    }
    echo "Key is: $key and Valus is: $value";
}

echo "<pre>";
print_r($array);
echo "</pre>";

?>
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  1. Editorial Team
    Editorial Team
    2026-05-19T04:24:25+00:00Added an answer on May 19, 2026 at 4:24 am

    You could just do

    $array = $_POST;
    

    since $_POST is already an array. However if you want to use the foreach loop to iterate a source array and copy only certain parts of it, you’d do something like:

    $new_array = array()
    foreach($original_array as $key => $value) {
        if (...filter condition(s)...) {
            $new_array[$key] = $value;
        }
    }
    

    There’s also array_map(), preg_grep(), etc… which you mangle/filter array as you please.

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