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Home/ Questions/Q 7733697
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T07:04:07+00:00 2026-06-01T07:04:07+00:00

I am downloading data from a php file using miniAjax. Here is what the

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I am downloading data from a php file using miniAjax. Here is what the beginning of the code looks like:

microAjax("genjsonphp.php", function(data) {
      var json = JSON.parse(data);
      var points = json;
//code continues

In java/android I am able to add information so that in the php file I can filter the data based off of user preferences:

nameValuePairs.add(new BasicNameValuePair("startd", startd));
    nameValuePairs.add(new BasicNameValuePair("endd", endd));
HttpClient httpclient = new DefaultHttpClient();
        // *************************************************************************************
        HttpPost httppost = new    HttpPost("http://someguyz.hostei.com/info.php");
//*************************************************************************************
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();     

How do I change my microAjax function so that I send information to the php file ‘genjsonphp.php’ in order to filter results? Is is similar as in java/android?

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  1. Editorial Team
    Editorial Team
    2026-06-01T07:04:08+00:00Added an answer on June 1, 2026 at 7:04 am

    I just checked on the platform hosted on code.google.com and from the looks of it, there is no way to pass parameter through post. But you can technically do through GET. modify you genjsonphp.php?param=1&param2=2 see if that works

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