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Home/ Questions/Q 1084611
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:35:07+00:00 2026-05-16T22:35:07+00:00

I am editing a Perl file, but I don’t understand this regexp comparison. Can

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I am editing a Perl file, but I don’t understand this regexp comparison. Can someone please explain it to me?

if ($lines =~ m/(.*?):(.*?)$/g) { } .. 

What happens here? $lines is a line from a text file.

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:35:07+00:00Added an answer on May 16, 2026 at 10:35 pm

    Break it up into parts:

    $lines =~ m/ (.*?)      # Match any character (except newlines)
                            # zero or more times, not greedily, and
                            # stick the results in $1.
                 :          # Match a colon.
                 (.*?)      # Match any character (except newlines)
                            # zero or more times, not greedily, and
                            # stick the results in $2.
                 $          # Match the end of the line.
               /gx;
    

    So, this will match strings like ":" (it matches zero characters, then a colon, then zero characters before the end of the line, $1 and $2 are empty strings), or "abc:" ($1 = "abc", $2 is an empty string), or "abc:def:ghi" ($1 = "abc" and $2 = "def:ghi").

    And if you pass in a line that doesn’t match (it looks like this would be if the string does not contain a colon), then it won’t process the code that’s within the brackets. But if it does match, then the code within the brackets can use and process the special $1 and $2 variables (at least, until the next regular expression shows up, if there is one within the brackets).

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