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Home/ Questions/Q 514765
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:33:31+00:00 2026-05-13T07:33:31+00:00

I am expecting that both following vectors have the same representation in RAM: char

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I am expecting that both following vectors have the same representation in RAM:

char a_var[] = "XXX\x00";
char *p_var  = "XXX";

But strange, a call to a library function of type f(char argument[]) crushs the running application if I call it using f(p_var). But using f(a_var) is Ok!

Why?

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:33:32+00:00Added an answer on May 13, 2026 at 7:33 am

    The first creates an array of char containing the string. The contents of the array can be modified. The second creates a character pointer which points to a string literal. String literals cannot be modified.

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