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Home/ Questions/Q 8166025
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T19:43:11+00:00 2026-06-06T19:43:11+00:00

I am facing a problem with urllib.url_encode in python. Bets explained with some code:

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I am facing a problem with urllib.url_encode in python. Bets explained with some code:

>>> from urllib import urlencode
>>> params = {'p' : '1 2 3 4 5&6', 'l' : 'ab|cd|ef'}
>>> urlencode(params)
'p=1+2+3+4+5%266&l=ab%7Ccd%7Cef'

I want to keep the pipes (‘|’) in to l parameter. can you please tell me how?

The result should be

'p=1+2+3+4+5%266&l=ab|cd|ef'

PS: I do not want to put together the URL manually, but use urlencode for that.

Thanks
-Pat

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  1. Editorial Team
    Editorial Team
    2026-06-06T19:43:13+00:00Added an answer on June 6, 2026 at 7:43 pm

    Convert a mapping object or a sequence of two-element tuples to a
    “percent-encoded” string[…]

    The urlencode() method is acting as expected. If you want to prevent the encoding then you can first encode the entire object and then replace the encoded characters with pipes.

    >>> u = urlencode(params)
    >>> u.replace('%7C', '|')
    'p=1+2+3+4+5%266&l=ab|cd|ef'  
    
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