Question

I am facing very confusing problem.

In my website all user have there own mail box which can be seen by them when they log in.

I have not assigned then any ids like [e-mail] or anything else.

They can send mails to each-other through their names only.

When they send a mail to diffrent user, it is saved as a data row in the database with the help of personid.

Now i want that if a user sends a mail to one other user, it should also automatically send a notification mail to the receiver’s external mail id.

I found the related code like

MailMessage mail = new MailMessage();
                    mail.To.Add("[e-mail]");
                    mail.From = new MailAddress("[e-mail]");
                    mail.Subject = "Send Email by asp.net code using google or gmail smtp server";
                    string Body = "Hi, I am testing Email function in asp.net";
                    mail.Body = Body;

                    SmtpClient smtp = new SmtpClient("localhost", 25);
                    smtp.Host = "smtp.gmail.com"; //Or Your SMTP Server Address  
                    smtp.Credentials = new System.Net.NetworkCredential
                         ("[e-mail]", "xxxxxxxxxxxxxx");
                    //Or your Smtp Email ID and Password  
                    smtp.DeliveryMethod = SmtpDeliveryMethod.Network;
                    smtp.EnableSsl = true;
                    smtp.Send(mail);
                    lblsuccess.Visible = true; 

It is working perfectly for me now..

Now i need to change the send field in

mail.From = new MailAddress("[e-mail]");

Because it can be any user without any email id like this.

What can i do for this..?

Answer 1

Retrieve the person/sender information from database by personid then put it on a variable list.

private class senderInformation{

 private string lastname;
 private string firstname;
 private string email;

}

senderInformation person = new senderInformation();

person.lastname = "Smith";
person.firstname = "John";
person.email= "[e-mail]";

mail.From = new MailAddress(person.email.toString());