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Home/ Questions/Q 7997625
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T15:00:27+00:00 2026-06-04T15:00:27+00:00

I am fairly new to Java and every time I try to compare input

  • 0

I am fairly new to Java and every time I try to compare input to temp, I get all of the results in my array, even if input and temp are not the same.

Code:

if (jRadioButton1.isSelected()) 
{ 
    String temp; 
    try
    {
        for (int i = 0; i < 500; i++)
        { 
            temp = Integer.toString(Read.tempHigh[i]);

            if ( input.equals(temp) );
            {   
                j.TextArea3.append(temp);
                j.TextArea3.append(input);
            }
        }
    }
    catch (NumberFormatException e)
    {   
        jTextArea3.append("Please enter a number");
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T15:00:28+00:00Added an answer on June 4, 2026 at 3:00 pm

    Your line…

    if ( input.equals(temp) );
    

    Should not have the ; at the end of it. The ; symbol is closing the if-statement off, so it will always run the j.TextArea3.append() lines no matter what the values of input and temp are.

    Your code above should therefore look like this…

    if (jRadioButton1.isSelected()){ 
        String temp; 
        try {
            for (int i = 0; i < 500; i++){ 
                temp = Integer.toString(Read.tempHigh[i]);
    
                if ( input.equals(temp) ) {   
                    j.TextArea3.append(temp);
                    j.TextArea3.append(input)
                }
            }
        }
        catch (NumberFormatException e){   
            jTextArea3.append("Please enter a number");
        }
    }
    
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