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Editorial Team
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Asked: 2026-06-04T09:18:06+00:00

I am fetching Google in a gadget using this code: <html> <head> <title>Browser</title> </head>

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I am fetching Google in a gadget using this code:

<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script>

function getListCollection() {
    var url = "https://www.google.co.uk"  
    xmlhttp = new XMLHttpRequest();
    xmlhttp.open('GET',url,true, 'user', 'password');
    xmlhttp.onreadystatechange = function()
    {
        if(xmlhttp.readyState == 4);
        {
            document.getElementById("listAttributes").innerHTML = xmlhttp.responseText
        }
    }
    xmlhttp.send(null);
}
</script>
</body>
</html>

I wonder how can I do the same thing using $ajax?

I looked at different examples but I don’t know how they gonna fit in this situation. Or if you can post some nice $ajax tutorials please.

When I change it to this, it doesn’t work:

<html>
<head>
<title>Browser</title>
</head>
<body onload= "getListCollection()" style="width:900px; height:900px;" >
<div id="listAttributes" style="width:400px; height:400px;" ></div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js">

$.ajax({
    url : 'https://www.google.co.uk',
    type : 'GET',
    success : function(data){
        $('#listAttributes').html(data);
    }
});
</script>
</body>
</html>

Nothing comes up on the page.

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1 Answer

  1. Editorial Team

    Here’s a jQuery version of the code:

    $.ajax({
    url : 'https://www.google.co.uk', //cross-domain? this won't work
    username : 'user',
    password : 'password',
    type : 'GET', //default is GET, but i put it here to clarify
    success : function(data){
        $('#listAttributes').html(data);
    }
});

    For more details and settings, read the jQuery.ajax() documentation

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