Question

I am fetching the datas from the database…And the datas are displayed as dropdownmenu but the css is not applied

---

  <ul id="nav">
  <?php
  $res=mysql_query("SELECT * FROM menu WHERE PARENT_ID=0");
  while($row=mysql_fetch_array($res))
  {
        echo "<li class='top'><a href='#' class='top_link'>".$row['MENU_NAME']."</a></li>";
    $res1=mysql_query("SELECT * FROM menu WHERE PARENT_ID=1 AND CHILD_ID=".$row['ID']."");

        while($row1=mysql_fetch_array($res1))
          {

             echo "<ul  class='sub'><li class='top'><a href='#' >".$row1['MENU_NAME']."</li></ul>";
             $res2=mysql_query("SELECT * FROM menu WHERE PARENT_ID=2 AND CHILD_ID=".$row1['ID']."");
             echo "<ul>";
             while($row2=mysql_fetch_array($res2))
                {
                        echo "<ul><li class='fly'><a href='#'>".$row2['MENU_NAME']."</li></ul>";
                }
             echo "</ul>";
          }
          echo "</ul>";
  }





  ?>
  </ul>
  <h1> </h1>


  <hr/>

this is my view page
my datas must be arranged in such a order that datas in the class=’top’ must be arrrived as as the main menu
the datas in the class=”sub” must be arrivd as submenu
the datas in the class=”fly” must be arrived as sub menu to the submenu
The format is
->main menu
-> submenu1->submenu11
->submenu12

-> submenu2
-> submenu3
when i give hard coded datas i am receiving in order that when i hover main menu
submenu will be displayed ..
the hard coded code is

Products

Cameras

• Nikon

when i hover submenu.. A submenu of the sub menu is be displayed
I got these results
How can apply the css to the datas fetchded from th database
my whole view page is

stu nicholls dot com | menu – Professional dropdown #2

Products

Cameras

• Nikon

---

  <ul id="nav">
  <?php
  $res=mysql_query("SELECT * FROM menu WHERE PARENT_ID=0");
  while($row=mysql_fetch_array($res))
  {
        echo "<li class='top'><a href='#' class='top_link'>".$row['MENU_NAME']."</a></li>";
    $res1=mysql_query("SELECT * FROM menu WHERE PARENT_ID=1 AND CHILD_ID=".$row['ID']."");

        while($row1=mysql_fetch_array($res1))
          {

             echo "<ul  class='sub'><li class='top'><a href='#' >".$row1['MENU_NAME']."</li></ul>";
             $res2=mysql_query("SELECT * FROM menu WHERE PARENT_ID=2 AND CHILD_ID=".$row1['ID']."");
             echo "<ul>";
             while($row2=mysql_fetch_array($res2))
                {
                        echo "<ul><li class='fly'><a href='#'>".$row2['MENU_NAME']."</li></ul>";
                }
             echo "</ul>";
          }
          echo "</ul>";
  }





  ?>
  </ul>
  <h1> </h1>


  <hr/>

Can anyone give me suggestion

Answer 1

Not directly a solution for your problem but why are you using a framework such as CI, which works around the MVC-principle and in the meantime have PHP and SQL statements in your view?

I suggest you read up on these CI topics:

• Template parser:
  https://www.codeigniter.com/userguide2/libraries/parser.html
• Database (active record):
  https://www.codeigniter.com/userguide2/database/active_record.html
• Views: https://www.codeigniter.com/userguide2/general/views.html

What’s the CSS you’re currently using?