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Home/ Questions/Q 7742421
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T09:16:17+00:00 2026-06-01T09:16:17+00:00

I am fetching the menucode from mysql database to android. if i clicking on

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I am fetching the menucode from mysql database to android. if i clicking on item in listview and codez=1 means it navigate to another page else go to another page

      JSONArray json = jArray.getJSONArray("mainmenu");

        final List<String> codez=new ArrayList<String>();
         for ( i = 0; i < json.length(); i++) {

                JSONObject e = json.getJSONObject(i);
                codez.add(e.getString("menucode"));



         }
       list.setOnItemClickListener(new OnItemClickListener() {   

        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
                long arg3) {
            System.out.println(codez);
            // TODO Auto-generated method stub
            if(codez.equals("1"))
            {
            Intent intent=new Intent(getApplicationContext(),FoodMenu.class);
            startActivity(intent);
            }else
            {

            }
        }
    });

it prints all codes but not navigate can u please tell me the solution for above code

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  1. Editorial Team
    Editorial Team
    2026-06-01T09:16:18+00:00Added an answer on June 1, 2026 at 9:16 am

    codez is a List, not a String. So when you try to compare it to "1", the comparison will always fail. Did you mean to choose one of the entries in the list instead?

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