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Home/ Questions/Q 6812023
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:23:58+00:00 2026-05-26T20:23:58+00:00

I am generating a feed using Zend Framework. When I am setting a link

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I am generating a feed using Zend Framework.

When I am setting a link like the one below, I get an error

$feed = new Zend_Feed_Writer_Feed;
$url = "http://www.example.com/search?s=chris|gayle|pics&device=1"
$feed->setLink($url);

I searched through Zend_Uri.php and Http.php, I was not able to figure out the problem.

exception ‘Zend_Feed_Exception’ with message ‘Invalid parameter:
parameter must be a non-empty string and valid URI/IRI’

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:23:58+00:00Added an answer on May 26, 2026 at 8:23 pm

    | is not allowed. Use %7C instead.

    For more info, see http://en.wikipedia.org/wiki/Percent-encoding#Types_of_URI_characters

    To encode a url use urlencode. This will make sure all characters are correctly encoded into a standard URI.

    http://php.net/manual/en/function.urlencode.php

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